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Compound of two icosahedra

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(Redirected from Compound of two dodecahedra) Polyhedral compound
Compound of two icosahedra
Type Uniform compound
Index UC46
Schläfli symbols β{3,4}
βr{3,3}
Coxeter diagrams
Polyhedra 2 icosahedra
Faces 16+24 triangles
Edges 60
Vertices 24
Symmetry group octahedral (Oh)
Subgroup restricting to one constituent pyritohedral (Th)
Holosnub octahedron, β{3,4}

This uniform polyhedron compound is a composition of 2 icosahedra. It has octahedral symmetry Oh. As a holosnub, it is represented by Schläfli symbol β{3,4} and Coxeter diagram .

The triangles in this compound decompose into two orbits under action of the symmetry group: 16 of the triangles lie in coplanar pairs in octahedral planes, while the other 24 lie in unique planes.

It shares the same vertex arrangement as a nonuniform truncated octahedron, having irregular hexagons alternating with long and short edges.


Nonuniform and uniform truncated octahedra. The first shares its vertex arrangement with this compound.

The icosahedron, as a uniform snub tetrahedron, is similar to these snub-pair compounds: compound of two snub cubes and compound of two snub dodecahedra.

Together with its convex hull, it represents the icosahedron-first projection of the nonuniform snub tetrahedral antiprism.

Cartesian coordinates

Cartesian coordinates for the vertices of this compound are all the permutations of

(±1, 0, ±τ)

where τ = (1+√5)/2 is the golden ratio (sometimes written φ).

Compound of two dodecahedra

The dual compound has two dodecahedra as pyritohedra in dual positions:

See also

References


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