| Revision as of 22:10, 23 October 2008 editHayson1991 (talk | contribs)242 edits →9← Previous edit | Latest revision as of 11:03, 6 July 2012 edit undoHayson1991 (talk | contribs)242 edits ←Blanked the page | ||
| (34 intermediate revisions by 6 users not shown) | |||
| Line 1: | Line 1: | ||
| <math>x = \tan\left(y\right)</math><br /><br /> | |||
| <math>1 = \sec^2\left(y\right)*\frac{dy}{dx}</math> (Chain rule, derivative of tan=sec^2)<br /><br /> | |||
| <math>\frac{1}{\sec^2\left(y\right)} = \frac{dy}{dx}</math><br /><br /> | |||
| <math>\cos^2\left(y\right) = \frac{dy}{dx}</math><br /><br /> | |||
| <math>\frac{dy}{dx} = \cos^2\left(y\right)</math><br /><br /> | |||
| == 9 == | |||
| x<sup>2</sup>y + xy<sup>2</sup> = 6 <span style="font-size: smaller;" class="autosigned">—Preceding ] comment added by ] (]) 22:03, 23 October 2008 (UTC)</span><!-- Template:UnsignedIP --> <!--Autosigned by SineBot--> | |||
| <math>x^{2}y + xy^2 = 6\,</math><br /><br /> | |||
| <math>\left(2x*y + x^{2}*\frac{dy}{dx}\right) + \left(1*y^2 + x*2y\frac{dy}{dx}\right) = 0</math><br /><br /> | |||
| <math>2xy + x^{2}\frac{dy}{dx} + y^2 + 2xy\frac{dy}{dx} = 0</math><br /><br /> | |||
| <math>x^{2}\frac{dy}{dx} + 2xy\frac{dy}{dx} = -2xy - y^2</math><br /><br /> | |||
| <math>\frac{dy}{dx} = \frac{-2xy - y^2}{x^{2} + 2xy}</math><br /><br /> | |||
| <math>\frac{dy}{dx} = -\frac{2xy + y^2}{x^{2} + 2xy}</math><br /><br /> | |||