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I wanted to avoid that E=.5*C*V^2 and E=.5*L*I^2 so said 'depending on' but that might be sacrificing accuracy for simplicty, and not that simple. other problems. Can anyone clean it up to usable form? ] 07:10, Mar 26, 2005 (UTC) | I wanted to avoid that E=.5*C*V^2 and E=.5*L*I^2 so said 'depending on' but that might be sacrificing accuracy for simplicty, and not that simple. other problems. Can anyone clean it up to usable form? ] 07:10, Mar 26, 2005 (UTC) | ||
:Looks fine to me. Just put it in and it will be tweaked as part of the article. |
:Looks fine to me. Just put it in and it will be tweaked as part of the article. — ] 14:58, August 22, 2005 (UTC) | ||
== Series and Parallel circuits == | == Series and Parallel circuits == | ||
The present page only covers a parallel tuned cicuit and is therfore not complete. | The present page only covers a parallel tuned cicuit and is therfore not complete. | ||
It should also include a series tuned circuit as these also come under the title | It should also include a series tuned circuit as these also come under the title |
Revision as of 05:12, 23 February 2006
I'd like to add this material but it may be too technical for the article.
- A capacitor stores energy in an electric field (depending on the voltage across it), an inductor stores energy in a magnetic field (depending on the current through it). If we start with a charged capacitor and connect an inductor across it, current will start to flow out of the capacitor (reducing the voltage across it) through the inductor, building up an magnetic field around the inductor. Eventually the capacitor will have no energy in it, but the inductor will be storing energy in its magnetic field. With no voltage across it the current will slow, and energy will be extracted from the magnetic field to keep the current flowing. Energy will therefore be extracted from the magnetic field, producing a current which will charge the capacitor with a voltage of opposite polarity to what it possessed originally. When the magnetic field is completely dissipated all the energy will again be stored in the capacitor (with the opposite polarity) and the process will repeat in reverse.
I wanted to avoid that E=.5*C*V^2 and E=.5*L*I^2 so said 'depending on' but that might be sacrificing accuracy for simplicty, and not that simple. other problems. Can anyone clean it up to usable form? RJFJR 07:10, Mar 26, 2005 (UTC)
- Looks fine to me. Just put it in and it will be tweaked as part of the article. — Omegatron 14:58, August 22, 2005 (UTC)
Series and Parallel circuits
The present page only covers a parallel tuned cicuit and is therfore not complete. It should also include a series tuned circuit as these also come under the title "LC circuit(s)". Light current 04:45, 2 August 2005 (UTC)