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Cheers.—] <span style="color:green;font-family:Rockwell">(])</span> 06:17, 10 September 2017 (UTC) | Cheers.—] <span style="color:green;font-family:Rockwell">(])</span> 06:17, 10 September 2017 (UTC) | ||
==Average dice== | ==Average dice throw== | ||
Section 5.1.2 of the article states: | Section 5.1.2 of the article states: | ||
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To roll a dice is a random event/process and in statistics, these events are not called average result, expected value would be the suitable/proper team. In short, to call it average result would be wrong. <!-- Template:Unsigned --><small class="autosigned">— Preceding ] comment added by ] (] • ]) 14:26, 17 September 2017 (UTC)</small> <!--Autosigned by SineBot--> | To roll a dice is a random event/process and in statistics, these events are not called average result, expected value would be the suitable/proper team. In short, to call it average result would be wrong. <!-- Template:Unsigned --><small class="autosigned">— Preceding ] comment added by ] (] • ]) 14:26, 17 September 2017 (UTC)</small> <!--Autosigned by SineBot--> | ||
:That's not what the use means. It's not talking about likeliness of outcomes, which, but the actual average (arithmetic mean) of all the possible sums. The use of the technical term needs better explanation. ] (]) 14:59, 17 September 2017 (UTC) | :That's not what the use means. It's not talking about likeliness of outcomes, which, but the actual average (arithmetic mean) of all the possible sums. The use of the technical term needs better explanation. ] (]) 14:59, 17 September 2017 (UTC) | ||
Hello Oknazevad, | |||
I don't agree. | |||
The paragraph it not referring to the likelihood of outcomes. The likelihood for each number for throwing a dice is 1/n. For a dice n=6. | |||
So the probability is 1/6. | |||
To roll a dice is in probability theory an event described by a uniform distribution. To find an average of a UD you have to sum up all possible outcomes and divide this by the count of outcomes: | |||
n=6 | |||
1+2+3+4+5+6=21 | |||
21/6= 3.5 | |||
This average what you get is called expected value. | |||
To get the expected value of throwing a dice in real you would have to roll the dice an infinite amount of throws than calculate the average of all throws. | |||
It doesn't matter if a 6 sided dice has 1-6 on its sides or 2,3,3,4,4,5. The expected value for both variants of dices is 3.5. | |||
Further, you state, the use of this technical term needs better explanation: | |||
This means you agree it is the proper term, but it's too difficult to understand? | |||
If the term expected value needs a better explanation what about to change the term into a hyperlink referring to an online encyclopedia (e.g. Misplaced Pages) explaining it? | |||
] (]) 14:06, 18 September 2017 (UTC) |
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There aren't mentions about De arte aleae Dawid2009 (talk) 13:28, 26 March 2017 (UTC)
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Average dice throw
Section 5.1.2 of the article states:
>>> A variation on the standard die is known as the "average" die. These are six-sided dice with sides numbered 2, 3, 3, 4, 4, 5, which results in the same average result as a standard die (3.5 for a single die, 7 for a pair of dice), but have a narrower range of possible values (2 through 5 for one, 4 through 10 for a pair). They are used in some table-top wargames, where a narrower range of numbers is required. <<<
To roll a dice is a random event/process and in statistics, these events are not called average result, expected value would be the suitable/proper team. In short, to call it average result would be wrong. — Preceding unsigned comment added by Da Vinci Nanjing (talk • contribs) 14:26, 17 September 2017 (UTC)
- That's not what the use means. It's not talking about likeliness of outcomes, which, but the actual average (arithmetic mean) of all the possible sums. The use of the technical term needs better explanation. oknazevad (talk) 14:59, 17 September 2017 (UTC)
Hello Oknazevad,
I don't agree.
The paragraph it not referring to the likelihood of outcomes. The likelihood for each number for throwing a dice is 1/n. For a dice n=6. So the probability is 1/6.
To roll a dice is in probability theory an event described by a uniform distribution. To find an average of a UD you have to sum up all possible outcomes and divide this by the count of outcomes:
n=6
1+2+3+4+5+6=21
21/6= 3.5
This average what you get is called expected value.
To get the expected value of throwing a dice in real you would have to roll the dice an infinite amount of throws than calculate the average of all throws.
It doesn't matter if a 6 sided dice has 1-6 on its sides or 2,3,3,4,4,5. The expected value for both variants of dices is 3.5.
Further, you state, the use of this technical term needs better explanation:
This means you agree it is the proper term, but it's too difficult to understand? If the term expected value needs a better explanation what about to change the term into a hyperlink referring to an online encyclopedia (e.g. Misplaced Pages) explaining it? Da Vinci Nanjing (talk) 14:06, 18 September 2017 (UTC)
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