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Revision as of 03:02, 26 March 2008 editHayson1991 (talk | contribs)242 editsNo edit summary← Previous edit Revision as of 02:43, 10 April 2008 edit undoHayson1991 (talk | contribs)242 editsNo edit summaryNext edit →
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<math>\frac{ \left( n+1 \right) 4^{2n+1}}{\left( n+2 \right) 4^{2n+3}}</math> <math>\frac{x^2}{a^3-x^3} = \frac{\frac{x^2}{a^3}}{1-\frac{x^3}{a^3}}</math>
<math>= \frac{ \left( n+1 \right) 4^{2n+1}}{\left( n+2 \right) 4^{2n+1} \cdot 4^{2}}</math>
<math>= \frac{ \left( n+1 \right)}{\left( n+2 \right) 4^{2}}</math>

Revision as of 02:43, 10 April 2008

x 2 a 3 − x 3 = x 2 a 3 1 − x 3 a 3 {\displaystyle {\frac {x^{2}}{a^{3}-x^{3}}}={\frac {\frac {x^{2}}{a^{3}}}{1-{\frac {x^{3}}{a^{3}}}}}}