< User talk:Hayson1991 Browse history interactively ← Previous edit Next edit → Content deleted Content addedVisual Wikitext Inline
Revision as of 21:54, 23 October 2008 edit Hayson1991 talk | contribs )242 editsNo edit summary← Previous edit Revision as of 21:55, 23 October 2008 edit undo Hayson1991 talk | contribs )242 editsNo edit summaryNext edit →
Line 2:
Line 2:
<math>1 = \sec^2\left(y\right)*\frac{dy}{dx}</math> (Chain rule, derivative of tan=sec^2)<br /><br />
<math>1 = \sec^2\left(y\right)*\frac{dy}{dx}</math> (Chain rule, derivative of tan=sec^2)<br /><br />
<math>\frac{1}{\sec^2\left(y\right)} = \frac{dy}{dx}</math><br /><br />
<math>\frac{1}{\sec^2\left(y\right)} = \frac{dy}{dx}</math><br /><br />
<math>\csc^2\left(y\right) = \frac{dy}{dx}</math><br /><br />
<math>\cos ^2\left(y\right) = \frac{dy}{dx}</math><br /><br />
<math>\frac{dy}{dx} = \csc^2\left(y\right)</math><br /><br />
<math>\frac{dy}{dx} = \cos ^2\left(y\right)</math><br /><br />
Revision as of 21:55, 23 October 2008
x
=
tan
(
y
)
{\displaystyle x=\tan \left(y\right)}
1
=
sec
2
(
y
)
∗
d
y
d
x
{\displaystyle 1=\sec ^{2}\left(y\right)*{\frac {dy}{dx}}}
1
sec
2
(
y
)
=
d
y
d
x
{\displaystyle {\frac {1}{\sec ^{2}\left(y\right)}}={\frac {dy}{dx}}}
cos
2
(
y
)
=
d
y
d
x
{\displaystyle \cos ^{2}\left(y\right)={\frac {dy}{dx}}}
d
y
d
x
=
cos
2
(
y
)
{\displaystyle {\frac {dy}{dx}}=\cos ^{2}\left(y\right)}
Text is available under the Creative Commons Attribution-ShareAlike License. Additional terms may apply.
**DISCLAIMER** We are not affiliated with Wikipedia, and Cloudflare.
The information presented on this site is for general informational purposes only and does not constitute medical advice.
You should always have a personal consultation with a healthcare professional before making changes to your diet, medication, or exercise routine.
AI helps with the correspondence in our chat.
We participate in an affiliate program. If you buy something through a link, we may earn a commission 💕
↑
(Chain rule, derivative of tan=sec^2)
