User talk:Hayson1991/mathpage: Difference between revisions

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Revision as of 21:55, 23 October 2008 editHayson1991 (talk \| contribs)242 editsNo edit summary← Previous edit		Revision as of 22:03, 23 October 2008 edit undo74.183.242.181 (talk) →9: new sectionNext edit →
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	<math>\cos^2\left(y\right) = \frac{dy}{dx}</math><br /><br />		<math>\cos^2\left(y\right) = \frac{dy}{dx}</math><br /><br />
	<math>\frac{dy}{dx} = \cos^2\left(y\right)</math><br /><br />		<math>\frac{dy}{dx} = \cos^2\left(y\right)</math><br /><br />

			== 9 ==

			x<sup>2</sup>y + xy<sup>2</sup> = 6

Revision as of 22:03, 23 October 2008

$x=\tan \left(y\right)$

$1=\sec ^{2}\left(y\right)*{\frac {dy}{dx}}$ (Chain rule, derivative of tan=sec^2)

${\frac {1}{\sec ^{2}\left(y\right)}}={\frac {dy}{dx}}$

$\cos ^{2}\left(y\right)={\frac {dy}{dx}}$

${\frac {dy}{dx}}=\cos ^{2}\left(y\right)$

9

xy + xy = 6