Misplaced Pages

User:DVdm: Difference between revisions

Article snapshot taken from Wikipedia with creative commons attribution-sharealike license. Give it a read and then ask your questions in the chat. We can research this topic together.
Browse history interactively← Previous editNext edit →Content deleted Content addedVisualWikitext
Revision as of 06:56, 10 October 2011 view sourceDVdm (talk | contribs)Autopatrolled, Extended confirmed users, New page reviewers, Pending changes reviewers, Rollbackers138,467 editsm inc← Previous edit Revision as of 09:03, 10 October 2011 view source 76.119.75.131 (talk) mind your own businessNext edit →
Line 1: Line 1:
Well, if he didn't undo a quality edit without bothering to even read/research it, I wouldn't have had to.
] (]) 09:03, 10 October 2011 (UTC)

{{Userboxtop|This...}} {{Userboxtop|This...}}
{{User:UBX/vandalized|39.5}} {{User:UBX/vandalized|39.5}}

Revision as of 09:03, 10 October 2011

Well, if he didn't undo a quality edit without bothering to even read/research it, I wouldn't have had to. 76.119.75.131 (talk) 09:03, 10 October 2011 (UTC)

This...
vn-39.5This user page has been vandalized 39.5 times.

A trivial refutation of one of Dingle's Fumbles (Ref: Talk:Herbert Dingle Archive)

On page 230 in this appendix to "Science At the Crossroads", Dingle writes:

(start quote)
Thus, between events E0 and E1, A advances by t1 and B by t'1 = a t1 by (1). Therefore
r a t e   o f   A r a t e   o f   B = t 1 a t 1 = 1 a > 1 ( 3 ) {\displaystyle {\frac {\color {OliveGreen}rate\ of\ A}{\color {Blue}rate\ of\ B}}={\frac {\color {OliveGreen}t_{1}}{\color {Blue}at_{1}}}={\frac {1}{a}}>1\qquad (3)}
...
Thus, between events E0 and E2, B advances by t'2 and A by t2 = a t'2 by (2). Therefore
r a t e   o f   A r a t e   o f   B = a t 2 t 2 = a < 1 ( 4 ) {\displaystyle {\frac {\color {Red}rate\ of\ A}{\color {Brown}rate\ of\ B}}={\frac {\color {Red}at'_{2}}{\color {Brown}t'_{2}}}=a<1\qquad (4)}
Equations (3) and (4) are contradictory: hence the theory requiring them must be false.
(end quote)

Dingle should have written as follows:

(start correction)
Thus, between events E0 and E1, A, which is not present at both events, advances by t1 and B, which is present at both events, by t'1 = a t1 by (1). Therefore
r a t e   o f   c l o c k   n o t   p r e s e n t   a t   b o t h   e v e n t s r a t e   o f   c l o c k   p r e s e n t   a t   b o t h   e v e n t s = c o o r d i n a t e   t i m e p r o p e r   t i m e = r a t e   o f   A r a t e   o f   B = t 1 a t 1 = 1 a > 1 ( 3 ) {\displaystyle {\frac {\color {OliveGreen}rate\ of\ clock\ not\ present\ at\ both\ events}{\color {Blue}rate\ of\ clock\ present\ at\ both\ events}}={\frac {\color {OliveGreen}coordinate\ time}{\color {Blue}proper\ time}}={\frac {\color {OliveGreen}rate\ of\ A}{\color {Blue}rate\ of\ B}}={\frac {\color {OliveGreen}t_{1}}{\color {Blue}at_{1}}}={\frac {1}{a}}>1\qquad (3)}
...
Thus, between events E0 and E2, B, which is not present at both events, advances by t'2 and A, which is present at both events, by t2 = a t'2 by (2). Therefore
r a t e   o f   c l o c k   n o t   p r e s e n t   a t   b o t h   e v e n t s r a t e   o f   c l o c k   p r e s e n t   a t   b o t h   e v e n t s = c o o r d i n a t e   t i m e p r o p e r   t i m e = r a t e   o f   B r a t e   o f   A = t 2 a t 2 = 1 a > 1 ( 4 ) {\displaystyle {\frac {\color {Brown}rate\ of\ clock\ not\ present\ at\ both\ events}{\color {Red}rate\ of\ clock\ present\ at\ both\ events}}={\frac {\color {Brown}coordinate\ time}{\color {Red}proper\ time}}={\frac {\color {Brown}rate\ of\ B}{\color {Red}rate\ of\ A}}={\frac {\color {Brown}t'_{2}}{\color {Red}at'_{2}}}={\frac {1}{a}}>1\qquad (4)}
Equations (3) and (4) are consistent: hence there is no reason to say that the theory requiring them must be false.
(end correction)

DVdm 12:18, 6 August 2007 (UTC)