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I think we can give $H exactly rather than estimate it: | I think we can give $H exactly rather than estimate it: | ||
:$H = H / (BFP - (HR + |
:$H = H / (BFP - (HR + K + BB + HB))) | ||
] 17:32, 27 March 2006 (UTC) | ] 17:32, 27 March 2006 (UTC) |
Revision as of 17:36, 27 March 2006
This is interesting, but where are the references? -JinAZ
Here is one (it was hard to find) WilliamKF 01:12, 27 March 2006 (UTC):
http://www.futilityinfielder.com/dipsexpl.html
The formula comes from Voros McCracken via Jay Jaffe (jay at futilityinfielder dot com).
I think we can give $H exactly rather than estimate it:
- $H = H / (BFP - (HR + K + BB + HB)))