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Revision as of 21:38, 28 November 2006 editMichael Hardy (talk | contribs)Administrators210,287 edits Without some convention of this kind, this concept seems rather vacuous. I have doubts about not only the usefulness of this concept, but its general respectability.← Previous edit Revision as of 21:38, 28 November 2006 edit undoMichael Hardy (talk | contribs)Administrators210,287 editsNo edit summaryNext edit →
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In ], the base-''b'' '''cologarithm''' of a number, sometimes shortened to '''colog''', is the base-''b'' ] of the ] of the number. This means that In ], the base-''b'' '''cologarithm''' of a number, sometimes shortened to '''colog''', is the base-''b'' ] of the ] of the number. This means that


:<math> \operatorname{colog}_b\ x = \log_b \left(\frac{1}{x} \right) = -\log_b x = \log_{1/b} x.\, </math> :<math> \operatorname{colog}_b\ x = \log_b \left(\frac{1}{x} \right) = -\log_b x.\, </math>


== References == == References ==

Revision as of 21:38, 28 November 2006

It has been suggested that this article be merged with Logarithm. (Discuss) Proposed since October 2006.

In mathematics, the base-b cologarithm of a number, sometimes shortened to colog, is the base-b logarithm of the multiplicative inverse of the number. This means that

colog b   x = log b ( 1 x ) = log b x . {\displaystyle \operatorname {colog} _{b}\ x=\log _{b}\left({\frac {1}{x}}\right)=-\log _{b}x.\,}

References

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