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User talk:Hayson1991/mathpage

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This is an old revision of this page, as edited by Hayson1991 (talk | contribs) at 02:31, 11 April 2008. The present address (URL) is a permanent link to this revision, which may differ significantly from the current revision.

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f ( x ) = ln ( 5 x ) {\displaystyle f(x)=\ln(5-x)\,}
d d x f ( x ) = 1 5 x = 1 1 ( x 4 ) = n = 0 ( x 4 ) n {\displaystyle {\frac {d}{dx}}f(x)=-{\frac {1}{5-x}}=-{\frac {1}{1-(x-4)}}=-\sum _{n=0}^{\infty }(x-4)^{n}\,}
d f ( x ) = ( n = 0 ( x 4 ) n ) d x {\displaystyle \int df(x)=\int \left(-\sum _{n=0}^{\infty }(x-4)^{n}\right)dx\,}
f ( x ) = C n = 0 ( x 4 ) n + 1 n + 1 {\displaystyle f(x)=C-\sum _{n=0}^{\infty }{\frac {(x-4)^{n+1}}{n+1}}\,}
f ( x ) = C n = 1 ( x 4 ) n n {\displaystyle f(x)=C-\sum _{n=1}^{\infty }{\frac {(x-4)^{n}}{n}}\,}