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${\displaystyle x=\tan \left(y\right)}$

${\displaystyle 1=\sec ^{2}\left(y\right)*{\frac {dy}{dx}}}$ (Chain rule, derivative of tan=sec^2)

${\displaystyle {\frac {1}{\sec ^{2}\left(y\right)}}={\frac {dy}{dx}}}$

${\displaystyle \cos ^{2}\left(y\right)={\frac {dy}{dx}}}$

${\displaystyle {\frac {dy}{dx}}=\cos ^{2}\left(y\right)}$

9

xy + xy = 6