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ACC promotion
How can I request to be promoted as a Admin on ACC? Venustas 12 (talk) 04:26, 27 January 2010 (UTC).
- The best way to be promoted to a tool admin is by proving your track record on the team. At the moment you have not been around for long (less than a month) and have only created 12 accounts. Regards -- Александр Дмитрий (Alexandr Dmitri) (talk) 04:55, 27 January 2010 (UTC)
Missing word
You have missed the word "satisfactory" (as in "satisfactory explanation") in your note to Craigy144, which I believe is integral to the spirit of the motion. –xeno 18:15, 28 January 2010 (UTC)
- Indeed I did and indeed it was. I have corrected the text on Craigy144's talkpage. Thank you for pointing that out to me. Regards -- Александр Дмитрий (Alexandr Dmitri) (talk) 18:30, 28 January 2010 (UTC)
- No problem, thanks for the fix. –xeno 15:19, 29 January 2010 (UTC)
Please save me
From blockshopping Last time same editor able to pose PhD in history highly prized by Jewish Foundation of Ukraine as "Russian nationalist writer". Here story appeared again. Thank you P.S. See that nice "balance" by Ukrainian Quarterly Spring 1964 or poet Moses Fishbein blog Jo0doe (talk) 19:05, 3 February 2010 (UTC)
- I'm not too sure at the moment exactly how I can help you, except to comment that if the allegations of publishing copyright material are true, then that is something which is not acceptable on Misplaced Pages. I'm not too sure either why you have come to me, as I have neither been involved on the articles in question as far as I can tell nor had contact with Moreschi. That said, if you feel that informal mediation is something that would help, then I am willing to offer my services. Regards -- Александр Дмитрий (Alexandr Dmitri) (talk) 22:16, 3 February 2010 (UTC)
- Material was not copyrighted (no copyright exist at site with motto knowlage not shared is lost)- and text comprised from the name of ships and thier tonnage. I ask about informal mediation - a kind of third party look at situation.If you advice me any posible solution I would be greatifull ThanksJo0doe (talk) 08:37, 4 February 2010 (UTC)
FYI
. Paul August ☎ 14:25, 9 February 2010 (UTC)
- Argh. Thanks. ---- Александр Дмитрий (Alexandr Dmitri) (talk) 14:58, 9 February 2010 (UTC)
Updated votes
This appears to actually not be passing... Cirt (talk) 19:23, 9 February 2010 (UTC)
- Thanks! Cirt (talk) 19:51, 9 February 2010 (UTC)
I have a question - how do you as a Clerk decide to place something as "not passing" versus "requiring further voting" ? Cirt (talk) 19:57, 9 February 2010 (UTC)
- (after two ec) Got caught out with SirFozzie's votes changing on a couple of points whilst I was updating the implementation notes with KnightLago's change of votes. I've corrected the proposed decision you pointed out as well as a FoF. Thanks! -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:12, 9 February 2010 (UTC)
- I put in "do not pass" what cannot pass; what is in "which require further voting" can go either way. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:12, 9 February 2010 (UTC)
- Ah, that makes sense. Thanks very much for the explanation, Cirt (talk) 20:21, 9 February 2010 (UTC)
- If that is the case then, it appears that this cannot pass? Cirt (talk) 20:22, 9 February 2010 (UTC)
- With three more arbitrators yet to vote it can go either way. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:28, 9 February 2010 (UTC)
- For this case, there are 13 active arbitrators, not counting 3 who are inactive and 1 who is recused, so 7 support votes are a majority. = there are two arbitrators left to vote. The remedy therefore cannot pass. Cirt (talk) 20:31, 9 February 2010 (UTC)
- I stand corrected on the number of arbitrators left to vote: it is indeed two. However there are already six supports. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:40, 9 February 2010 (UTC)
- Yes, however there are also 3 opposes. 8 - 3 = 5. Cirt (talk) 20:41, 9 February 2010 (UTC)
- That's not how it works. Majority means one more supports than opposes, not 7 more supports than opposes. So it is 7 supports out of 13 that is a majority; if people abstain then the number of supports required also diminishes. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:46, 9 February 2010 (UTC)
- Yes, however there are also 3 opposes. 8 - 3 = 5. Cirt (talk) 20:41, 9 February 2010 (UTC)
- I stand corrected on the number of arbitrators left to vote: it is indeed two. However there are already six supports. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:40, 9 February 2010 (UTC)
- For this case, there are 13 active arbitrators, not counting 3 who are inactive and 1 who is recused, so 7 support votes are a majority. = there are two arbitrators left to vote. The remedy therefore cannot pass. Cirt (talk) 20:31, 9 February 2010 (UTC)
- With three more arbitrators yet to vote it can go either way. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:28, 9 February 2010 (UTC)
- If that is the case then, it appears that this cannot pass? Cirt (talk) 20:22, 9 February 2010 (UTC)
- Ah, that makes sense. Thanks very much for the explanation, Cirt (talk) 20:21, 9 February 2010 (UTC)
- I put in "do not pass" what cannot pass; what is in "which require further voting" can go either way. -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:12, 9 February 2010 (UTC)
AlexandrDmitri, thank you very much for your helpful, kind and polite explanations during all this. Cirt (talk) 22:10, 9 February 2010 (UTC)
6A passing
For the case "MZMcBride 2", by my count, Finding 6A is currently passing with 6 supports, 1 abstain and 1 recusal. Paul August ☎ 20:23, 9 February 2010 (UTC)
- For this case, there are 13 active arbitrators, not counting 3 who are inactive and 1 who is recused, so 7 support votes are a majority. = this says the recusals should not be used in the count. Cirt (talk) 20:28, 9 February 2010 (UTC)
- As I said to your post on my talk page, "There is one arb recused on the entire case, Cool Hand Luke, and three arbs inactive Carcharoth , Hersfold , and Wizardman. That leaves 13 active arbs for this case. However on finding 6A, Risker has recused and Mailer Diablo has abstained. That leaves 11 arbs active on this particular finding, thus the majority for this finding is 6." Paul August ☎ 20:40, 9 February 2010 (UTC)
- 6a updated -- Александр Дмитрий (Alexandr Dmitri) (talk) 20:49, 9 February 2010 (UTC)