Misplaced Pages

Accumulation point

Article snapshot taken from Wikipedia with creative commons attribution-sharealike license. Give it a read and then ask your questions in the chat. We can research this topic together.
(Redirected from Complete accumulation point) Cluster point in a topological space "Limit point" redirects here. For uses where the word "point" is optional, see Limit (mathematics) and Limit (disambiguation) § Mathematics.

In mathematics, a limit point, accumulation point, or cluster point of a set S {\displaystyle S} in a topological space X {\displaystyle X} is a point x {\displaystyle x} that can be "approximated" by points of S {\displaystyle S} in the sense that every neighbourhood of x {\displaystyle x} contains a point of S {\displaystyle S} other than x {\displaystyle x} itself. A limit point of a set S {\displaystyle S} does not itself have to be an element of S . {\displaystyle S.} There is also a closely related concept for sequences. A cluster point or accumulation point of a sequence ( x n ) n N {\displaystyle (x_{n})_{n\in \mathbb {N} }} in a topological space X {\displaystyle X} is a point x {\displaystyle x} such that, for every neighbourhood V {\displaystyle V} of x , {\displaystyle x,} there are infinitely many natural numbers n {\displaystyle n} such that x n V . {\displaystyle x_{n}\in V.} This definition of a cluster or accumulation point of a sequence generalizes to nets and filters.

The similarly named notion of a limit point of a sequence (respectively, a limit point of a filter, a limit point of a net) by definition refers to a point that the sequence converges to (respectively, the filter converges to, the net converges to). Importantly, although "limit point of a set" is synonymous with "cluster/accumulation point of a set", this is not true for sequences (nor nets or filters). That is, the term "limit point of a sequence" is not synonymous with "cluster/accumulation point of a sequence".

The limit points of a set should not be confused with adherent points (also called points of closure) for which every neighbourhood of x {\displaystyle x} contains some point of S {\displaystyle S} . Unlike for limit points, an adherent point x {\displaystyle x} of S {\displaystyle S} may have a neighbourhood not containing points other than x {\displaystyle x} itself. A limit point can be characterized as an adherent point that is not an isolated point.

Limit points of a set should also not be confused with boundary points. For example, 0 {\displaystyle 0} is a boundary point (but not a limit point) of the set { 0 } {\displaystyle \{0\}} in R {\displaystyle \mathbb {R} } with standard topology. However, 0.5 {\displaystyle 0.5} is a limit point (though not a boundary point) of interval [ 0 , 1 ] {\displaystyle } in R {\displaystyle \mathbb {R} } with standard topology (for a less trivial example of a limit point, see the first caption).

This concept profitably generalizes the notion of a limit and is the underpinning of concepts such as closed set and topological closure. Indeed, a set is closed if and only if it contains all of its limit points, and the topological closure operation can be thought of as an operation that enriches a set by uniting it with its limit points.

With respect to the usual Euclidean topology, the sequence of rational numbers x n = ( 1 ) n n n + 1 {\displaystyle x_{n}=(-1)^{n}{\frac {n}{n+1}}} has no limit (i.e. does not converge), but has two accumulation points (which are considered limit points here), viz. -1 and +1. Thus, thinking of sets, these points are limit points of the set S = { x n } . {\displaystyle S=\{x_{n}\}.}

Definition

Accumulation points of a set

A sequence enumerating all positive rational numbers. Each positive real number is a cluster point.

Let S {\displaystyle S} be a subset of a topological space X . {\displaystyle X.} A point x {\displaystyle x} in X {\displaystyle X} is a limit point or cluster point or accumulation point of the set S {\displaystyle S} if every neighbourhood of x {\displaystyle x} contains at least one point of S {\displaystyle S} different from x {\displaystyle x} itself.

It does not make a difference if we restrict the condition to open neighbourhoods only. It is often convenient to use the "open neighbourhood" form of the definition to show that a point is a limit point and to use the "general neighbourhood" form of the definition to derive facts from a known limit point.

If X {\displaystyle X} is a T 1 {\displaystyle T_{1}} space (such as a metric space), then x X {\displaystyle x\in X} is a limit point of S {\displaystyle S} if and only if every neighbourhood of x {\displaystyle x} contains infinitely many points of S . {\displaystyle S.} In fact, T 1 {\displaystyle T_{1}} spaces are characterized by this property.

If X {\displaystyle X} is a Fréchet–Urysohn space (which all metric spaces and first-countable spaces are), then x X {\displaystyle x\in X} is a limit point of S {\displaystyle S} if and only if there is a sequence of points in S { x } {\displaystyle S\setminus \{x\}} whose limit is x . {\displaystyle x.} In fact, Fréchet–Urysohn spaces are characterized by this property.

The set of limit points of S {\displaystyle S} is called the derived set of S . {\displaystyle S.}

Special types of accumulation point of a set

If every neighbourhood of x {\displaystyle x} contains infinitely many points of S , {\displaystyle S,} then x {\displaystyle x} is a specific type of limit point called an ω-accumulation point of S . {\displaystyle S.}

If every neighbourhood of x {\displaystyle x} contains uncountably many points of S , {\displaystyle S,} then x {\displaystyle x} is a specific type of limit point called a condensation point of S . {\displaystyle S.}

If every neighbourhood U {\displaystyle U} of x {\displaystyle x} is such that the cardinality of U S {\displaystyle U\cap S} equals the cardinality of S , {\displaystyle S,} then x {\displaystyle x} is a specific type of limit point called a complete accumulation point of S . {\displaystyle S.}

Accumulation points of sequences and nets

See also: Net (mathematics) § Cluster point of a net, and Cluster point of a filter

In a topological space X , {\displaystyle X,} a point x X {\displaystyle x\in X} is said to be a cluster point or accumulation point of a sequence x = ( x n ) n = 1 {\displaystyle x_{\bullet }=\left(x_{n}\right)_{n=1}^{\infty }} if, for every neighbourhood V {\displaystyle V} of x , {\displaystyle x,} there are infinitely many n N {\displaystyle n\in \mathbb {N} } such that x n V . {\displaystyle x_{n}\in V.} It is equivalent to say that for every neighbourhood V {\displaystyle V} of x {\displaystyle x} and every n 0 N , {\displaystyle n_{0}\in \mathbb {N} ,} there is some n n 0 {\displaystyle n\geq n_{0}} such that x n V . {\displaystyle x_{n}\in V.} If X {\displaystyle X} is a metric space or a first-countable space (or, more generally, a Fréchet–Urysohn space), then x {\displaystyle x} is a cluster point of x {\displaystyle x_{\bullet }} if and only if x {\displaystyle x} is a limit of some subsequence of x . {\displaystyle x_{\bullet }.} The set of all cluster points of a sequence is sometimes called the limit set.

Note that there is already the notion of limit of a sequence to mean a point x {\displaystyle x} to which the sequence converges (that is, every neighborhood of x {\displaystyle x} contains all but finitely many elements of the sequence). That is why we do not use the term limit point of a sequence as a synonym for accumulation point of the sequence.

The concept of a net generalizes the idea of a sequence. A net is a function f : ( P , ) X , {\displaystyle f:(P,\leq )\to X,} where ( P , ) {\displaystyle (P,\leq )} is a directed set and X {\displaystyle X} is a topological space. A point x X {\displaystyle x\in X} is said to be a cluster point or accumulation point of a net f {\displaystyle f} if, for every neighbourhood V {\displaystyle V} of x {\displaystyle x} and every p 0 P , {\displaystyle p_{0}\in P,} there is some p p 0 {\displaystyle p\geq p_{0}} such that f ( p ) V , {\displaystyle f(p)\in V,} equivalently, if f {\displaystyle f} has a subnet which converges to x . {\displaystyle x.} Cluster points in nets encompass the idea of both condensation points and ω-accumulation points. Clustering and limit points are also defined for filters.

Relation between accumulation point of a sequence and accumulation point of a set

Every sequence x = ( x n ) n = 1 {\displaystyle x_{\bullet }=\left(x_{n}\right)_{n=1}^{\infty }} in X {\displaystyle X} is by definition just a map x : N X {\displaystyle x_{\bullet }:\mathbb {N} \to X} so that its image Im x := { x n : n N } {\displaystyle \operatorname {Im} x_{\bullet }:=\left\{x_{n}:n\in \mathbb {N} \right\}} can be defined in the usual way.

  • If there exists an element x X {\displaystyle x\in X} that occurs infinitely many times in the sequence, x {\displaystyle x} is an accumulation point of the sequence. But x {\displaystyle x} need not be an accumulation point of the corresponding set Im x . {\displaystyle \operatorname {Im} x_{\bullet }.} For example, if the sequence is the constant sequence with value x , {\displaystyle x,} we have Im x = { x } {\displaystyle \operatorname {Im} x_{\bullet }=\{x\}} and x {\displaystyle x} is an isolated point of Im x {\displaystyle \operatorname {Im} x_{\bullet }} and not an accumulation point of Im x . {\displaystyle \operatorname {Im} x_{\bullet }.}
  • If no element occurs infinitely many times in the sequence, for example if all the elements are distinct, any accumulation point of the sequence is an ω {\displaystyle \omega } -accumulation point of the associated set Im x . {\displaystyle \operatorname {Im} x_{\bullet }.}

Conversely, given a countable infinite set A X {\displaystyle A\subseteq X} in X , {\displaystyle X,} we can enumerate all the elements of A {\displaystyle A} in many ways, even with repeats, and thus associate with it many sequences x {\displaystyle x_{\bullet }} that will satisfy A = Im x . {\displaystyle A=\operatorname {Im} x_{\bullet }.}

  • Any ω {\displaystyle \omega } -accumulation point of A {\displaystyle A} is an accumulation point of any of the corresponding sequences (because any neighborhood of the point will contain infinitely many elements of A {\displaystyle A} and hence also infinitely many terms in any associated sequence).
  • A point x X {\displaystyle x\in X} that is not an ω {\displaystyle \omega } -accumulation point of A {\displaystyle A} cannot be an accumulation point of any of the associated sequences without infinite repeats (because x {\displaystyle x} has a neighborhood that contains only finitely many (possibly even none) points of A {\displaystyle A} and that neighborhood can only contain finitely many terms of such sequences).

Properties

Every limit of a non-constant sequence is an accumulation point of the sequence. And by definition, every limit point is an adherent point.

The closure cl ( S ) {\displaystyle \operatorname {cl} (S)} of a set S {\displaystyle S} is a disjoint union of its limit points L ( S ) {\displaystyle L(S)} and isolated points I ( S ) {\displaystyle I(S)} ; that is, cl ( S ) = L ( S ) I ( S ) and L ( S ) I ( S ) = . {\displaystyle \operatorname {cl} (S)=L(S)\cup I(S)\quad {\text{and}}\quad L(S)\cap I(S)=\emptyset .}

A point x X {\displaystyle x\in X} is a limit point of S X {\displaystyle S\subseteq X} if and only if it is in the closure of S { x } . {\displaystyle S\setminus \{x\}.}

Proof

We use the fact that a point is in the closure of a set if and only if every neighborhood of the point meets the set. Now, x {\displaystyle x} is a limit point of S , {\displaystyle S,} if and only if every neighborhood of x {\displaystyle x} contains a point of S {\displaystyle S} other than x , {\displaystyle x,} if and only if every neighborhood of x {\displaystyle x} contains a point of S { x } , {\displaystyle S\setminus \{x\},} if and only if x {\displaystyle x} is in the closure of S { x } . {\displaystyle S\setminus \{x\}.}

If we use L ( S ) {\displaystyle L(S)} to denote the set of limit points of S , {\displaystyle S,} then we have the following characterization of the closure of S {\displaystyle S} : The closure of S {\displaystyle S} is equal to the union of S {\displaystyle S} and L ( S ) . {\displaystyle L(S).} This fact is sometimes taken as the definition of closure.

Proof

("Left subset") Suppose x {\displaystyle x} is in the closure of S . {\displaystyle S.} If x {\displaystyle x} is in S , {\displaystyle S,} we are done. If x {\displaystyle x} is not in S , {\displaystyle S,} then every neighbourhood of x {\displaystyle x} contains a point of S , {\displaystyle S,} and this point cannot be x . {\displaystyle x.} In other words, x {\displaystyle x} is a limit point of S {\displaystyle S} and x {\displaystyle x} is in L ( S ) . {\displaystyle L(S).}

("Right subset") If x {\displaystyle x} is in S , {\displaystyle S,} then every neighbourhood of x {\displaystyle x} clearly meets S , {\displaystyle S,} so x {\displaystyle x} is in the closure of S . {\displaystyle S.} If x {\displaystyle x} is in L ( S ) , {\displaystyle L(S),} then every neighbourhood of x {\displaystyle x} contains a point of S {\displaystyle S} (other than x {\displaystyle x} ), so x {\displaystyle x} is again in the closure of S . {\displaystyle S.} This completes the proof.

A corollary of this result gives us a characterisation of closed sets: A set S {\displaystyle S} is closed if and only if it contains all of its limit points.

Proof

Proof 1: S {\displaystyle S} is closed if and only if S {\displaystyle S} is equal to its closure if and only if S = S L ( S ) {\displaystyle S=S\cup L(S)} if and only if L ( S ) {\displaystyle L(S)} is contained in S . {\displaystyle S.}

Proof 2: Let S {\displaystyle S} be a closed set and x {\displaystyle x} a limit point of S . {\displaystyle S.} If x {\displaystyle x} is not in S , {\displaystyle S,} then the complement to S {\displaystyle S} comprises an open neighbourhood of x . {\displaystyle x.} Since x {\displaystyle x} is a limit point of S , {\displaystyle S,} any open neighbourhood of x {\displaystyle x} should have a non-trivial intersection with S . {\displaystyle S.} However, a set can not have a non-trivial intersection with its complement. Conversely, assume S {\displaystyle S} contains all its limit points. We shall show that the complement of S {\displaystyle S} is an open set. Let x {\displaystyle x} be a point in the complement of S . {\displaystyle S.} By assumption, x {\displaystyle x} is not a limit point, and hence there exists an open neighbourhood U {\displaystyle U} of x {\displaystyle x} that does not intersect S , {\displaystyle S,} and so U {\displaystyle U} lies entirely in the complement of S . {\displaystyle S.} Since this argument holds for arbitrary x {\displaystyle x} in the complement of S , {\displaystyle S,} the complement of S {\displaystyle S} can be expressed as a union of open neighbourhoods of the points in the complement of S . {\displaystyle S.} Hence the complement of S {\displaystyle S} is open.

No isolated point is a limit point of any set.

Proof

If x {\displaystyle x} is an isolated point, then { x } {\displaystyle \{x\}} is a neighbourhood of x {\displaystyle x} that contains no points other than x . {\displaystyle x.}

A space X {\displaystyle X} is discrete if and only if no subset of X {\displaystyle X} has a limit point.

Proof

If X {\displaystyle X} is discrete, then every point is isolated and cannot be a limit point of any set. Conversely, if X {\displaystyle X} is not discrete, then there is a singleton { x } {\displaystyle \{x\}} that is not open. Hence, every open neighbourhood of { x } {\displaystyle \{x\}} contains a point y x , {\displaystyle y\neq x,} and so x {\displaystyle x} is a limit point of X . {\displaystyle X.}

If a space X {\displaystyle X} has the trivial topology and S {\displaystyle S} is a subset of X {\displaystyle X} with more than one element, then all elements of X {\displaystyle X} are limit points of S . {\displaystyle S.} If S {\displaystyle S} is a singleton, then every point of X S {\displaystyle X\setminus S} is a limit point of S . {\displaystyle S.}

Proof

As long as S { x } {\displaystyle S\setminus \{x\}} is nonempty, its closure will be X . {\displaystyle X.} It is only empty when S {\displaystyle S} is empty or x {\displaystyle x} is the unique element of S . {\displaystyle S.}

See also

  • Adherent point – Point that belongs to the closure of some given subset of a topological space
  • Condensation point – a stronger analog of limit pointPages displaying wikidata descriptions as a fallback
  • Convergent filter – Use of filters to describe and characterize all basic topological notions and results.Pages displaying short descriptions of redirect targets
  • Derived set (mathematics) – Set of all limit points of a set
  • Filters in topology – Use of filters to describe and characterize all basic topological notions and results.
  • Isolated point – Point of a subset S around which there are no other points of S
  • Limit of a function – Point to which functions converge in analysis
  • Limit of a sequence – Value to which tends an infinite sequence
  • Subsequential limit – The limit of some subsequence

Citations

  1. Dugundji 1966, pp. 209–210.
  2. Bourbaki 1989, pp. 68–83.
  3. "Difference between boundary point & limit point". 2021-01-13.
  4. "What is a limit point". 2021-01-13.
  5. "Examples of Accumulation Points". 2021-01-13. Archived from the original on 2021-04-21. Retrieved 2021-01-14.
  6. Munkres 2000, pp. 97–102.

References

Topology
Fields Computer graphics rendering of a Klein bottle
Key concepts
Metrics and properties
Key results
Categories: