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(Redirected from Spoof odd perfect number)
Number which would have been an odd perfect number if one of its composite factors were prime
where we ignore the fact that 22021 is composite (22021 = 19 ⋅ 61).
A Descartes number is defined as an odd number n = m ⋅ p where m and p are coprime and 2n = σ(m) ⋅ (p + 1), whence p is taken as a 'spoof' prime. The example given is the only one currently known.
If m is an odd almost perfect number, that is, σ(m) = 2m − 1 and 2m − 1 is taken as a 'spoof' prime, then n = m ⋅ (2m − 1) is a Descartes number, since σ(n) = σ(m ⋅ (2m − 1)) = σ(m) ⋅ 2m = (2m − 1) ⋅ 2m = 2n. If 2m − 1 were prime, n would be an odd perfect number.
Properties
Banks et al. showed in 2008 that if n is a cube-free Descartes number not divisible by , then n has over one million distinct prime divisors.
Tóth showed in 2021 that if denotes a Descartes number (other than Descartes’ example), with pseudo-prime factor , then .
Generalizations
John Voight generalized Descartes numbers to allow negative bases. He found the example . Subsequent work by a group at Brigham Young University found more examples similar to Voight's example, and also allowed a new class of spoofs where one is allowed to also not notice that a prime is the same as another prime in the factorization.
Currently, the only known almost perfect numbers are the non-negative powers of 2, whence the only known odd almost perfect number is 2 = 1.
Banks, William D.; Güloğlu, Ahmet M.; Nevans, C. Wesley; Saidak, Filip (2008), "Descartes numbers", Anatomy of integers. Based on the CRM workshop, Montreal, Canada, March 13–17, 2006, Providence, RI: American Mathematical Society (AMS), pp. 167–173, ISBN978-0-8218-4406-9, Zbl1186.11004, retrieved 2024-05-13