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1796 United States presidential election in New Hampshire

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Main article: 1796 United States presidential election
1796 United States presidential election in New Hampshire

← 1792 November 4 – December 7, 1796 1800 →
 
Nominee John Adams Thomas Jefferson
Party Federalist Democratic-Republican
Home state Massachusetts Virginia
Running mate Thomas Pinckney Aaron Burr
Electoral vote 6 0
Popular vote 3,265 393
Percentage 89.3% 10.7%

President before election

George Washington
Independent

Elected President

John Adams
Federalist

The 1796 United States presidential election in New Hampshire took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

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New Hampshire voted for Federalist candidate and Vice President John Adams, over the Democratic-Republican candidate and Secretary of State Thomas Jefferson by a total of 78.6% margin of the popular vote, making this the largest margin for a presidential candidate in the state of New Hampshire.

Results

1796 United States presidential election in New Hampshire
Party Candidate Votes Percentage Electoral votes
Federalist John Adams 3,265 89.3% 6
Democratic-Republican Thomas Jefferson 393 10.7%
Totals 3,658 100.0% 6

See also

References

  1. ^ "Presidential Results: National, 1796". votearchive.com. Retrieved 2024-06-20.
State results of the 1796 U.S. presidential election
Candidates Electoral map, 1796 election
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