1836 United States presidential election in Indiana

Main article: 1836 United States presidential election

November 3 – December 7, 1836


Nominee	William Henry Harrison	Martin Van Buren
Party	Whig	Democratic
Home state	Ohio	New York
Running mate	Francis Granger	Richard Johnson
Electoral vote	9	0
Popular vote	41,281	32,478
Percentage	55.97%	44.03%

County Results

Harrison

50-60% 60-70% 70–80%

Van Buren

50-60% 60-70% 70-80%

Unknown/No vote

Elections in Indiana

Federal government

Presidential elections
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State government

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Gubernatorial elections
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Indianapolis

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Other localities

Carmel (mayoral)
Evansville (mayoral)
Fort Wayne (mayoral)
Gary (mayoral)
South Bend (mayoral)
v t e

The 1836 United States presidential election in Indiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

Indiana voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Indiana by a margin of 11.94%.

Results

1836 United States presidential election in Indiana
Party		Candidate	Votes	Percentage	Electoral votes
	Whig	William Henry Harrison	41,281	55.97%	9
	Democratic	Martin Van Buren	32,478	44.03%	0
Totals			73,759	100.0%	9

References

"1836 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved August 4, 2012.

v t e State and district results of the 1836 United States presidential election
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References