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Elongated triangular pyramid

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Polyhedron constructed with tetrahedra and a triangular prism
Elongated triangular pyramid
TypeJohnson
J6J7J8
Faces4 triangles
3 squares
Edges12
Vertices7
Vertex configuration1(3)
3(3.4)
3(3.4)
Symmetry groupC3v, , (*33)
Rotation groupC3, , (33)
Dual polyhedronself
Propertiesconvex
Net
Johnson solid J7.

In geometry, the elongated triangular pyramid is one of the Johnson solids (J7). As the name suggests, it can be constructed by elongating a tetrahedron by attaching a triangular prism to its base. Like any elongated pyramid, the resulting solid is topologically (but not geometrically) self-dual.

Construction

The elongated triangular pyramid is constructed from a triangular prism by attaching regular tetrahedron onto one of its bases, a process known as elongation. The tetrahedron covers an equilateral triangle, replacing it with three other equilateral triangles, so that the resulting polyhedron has four equilateral triangles and three squares as its faces. A convex polyhedron in which all of the faces are regular polygons is called the Johnson solid, and the elongated triangular pyramid is among them, enumerated as the seventh Johnson solid J 7 {\displaystyle J_{7}} .

Properties

An elongated triangular pyramid with edge length a {\displaystyle a} has a height, by adding the height of a regular tetrahedron and a triangular prism: ( 1 + 6 3 ) a 1.816 a . {\displaystyle \left(1+{\frac {\sqrt {6}}{3}}\right)a\approx 1.816a.} Its surface area can be calculated by adding the area of all eight equilateral triangles and three squares: ( 3 + 3 ) a 2 4.732 a 2 , {\displaystyle \left(3+{\sqrt {3}}\right)a^{2}\approx 4.732a^{2},} and its volume can be calculated by slicing it into a regular tetrahedron and a prism, adding their volume up:: ( 1 12 ( 2 + 3 3 ) ) a 3 0.551 a 3 . {\displaystyle \left({\frac {1}{12}}\left({\sqrt {2}}+3{\sqrt {3}}\right)\right)a^{3}\approx 0.551a^{3}.}

It has the three-dimensional symmetry group, the cyclic group C 3 v {\displaystyle C_{3\mathrm {v} }} of order 6. Its dihedral angle can be calculated by adding the angle of the tetrahedron and the triangular prism:

  • the dihedral angle of a tetrahedron between two adjacent triangular faces is arccos ( 1 3 ) 70.5 {\textstyle \arccos \left({\frac {1}{3}}\right)\approx 70.5^{\circ }} ;
  • the dihedral angle of the triangular prism between the square to its bases is π 2 = 90 {\textstyle {\frac {\pi }{2}}=90^{\circ }} , and the dihedral angle between square-to-triangle, on the edge where tetrahedron and triangular prism are attached, is arccos ( 1 3 ) + π 2 160.5 {\textstyle \arccos \left({\frac {1}{3}}\right)+{\frac {\pi }{2}}\approx 160.5^{\circ }} ;
  • the dihedral angle of the triangular prism between two adjacent square faces is the internal angle of an equilateral triangle π 3 = 60 {\textstyle {\frac {\pi }{3}}=60^{\circ }} .

References

  1. Rajwade, A. R. (2001). Convex Polyhedra with Regularity Conditions and Hilbert's Third Problem. Texts and Readings in Mathematics. Hindustan Book Agency. p. 84–89. doi:10.1007/978-93-86279-06-4. ISBN 978-93-86279-06-4.
  2. ^ Berman, Martin (1971). "Regular-faced convex polyhedra". Journal of the Franklin Institute. 291 (5): 329–352. doi:10.1016/0016-0032(71)90071-8. MR 0290245.
  3. Uehara, Ryuhei (2020). Introduction to Computational Origami: The World of New Computational Geometry. Springer. p. 62. doi:10.1007/978-981-15-4470-5. ISBN 978-981-15-4470-5. S2CID 220150682.
  4. Sapiña, R. "Area and volume of the Johnson solid J 8 {\displaystyle J_{8}} ". Problemas y Ecuaciones (in Spanish). ISSN 2659-9899. Retrieved 2020-09-09.
  5. Johnson, Norman W. (1966). "Convex polyhedra with regular faces". Canadian Journal of Mathematics. 18: 169–200. doi:10.4153/cjm-1966-021-8. MR 0185507. S2CID 122006114. Zbl 0132.14603.


External links

Johnson solids
Pyramids, cupolae and rotundae
Modified pyramids
Modified cupolae and rotundae
Augmented prisms
Modified Platonic solids
Modified Archimedean solids
Other elementary solids
(See also List of Johnson solids, a sortable table)
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